debugger quad evaluation

[Chris Holbrook]

The debuggeriser tells me that a quad integer has a value 5.something 4E+16, (hexval 0). The attached picture saya it better.

I don't understand!

[George Bleck]

It is scientific notation for computing...

1E+2 = 100 (read as 1 X 10^2)
1E-2 = .01 (read as 1 X 10^-2)
6.261E+4 = 62610
3.74E-3 = .00374

Another way of looking at it is if the number after "E" is positive move the decimal to the right that many places based on the number after the "E".

Do the reverse if it is negative after the "E" move it to the left that many places.

[Paul Dixon]

It looks like a minor bug in the IDE.
The decimal value of the number is being converted to HEX using only 32bits (the usual range for the HEX$ command) but a QUAD needs 64 bits to show it fully.

Paul.

[Chris Holbrook]

It looks like a minor bug in the IDE.
The decimal value of the number is being converted to HEX using only 32bits

but the hex and decimal (mantissa/exponent) values are inconsistent with each other - if the QUAD has a value of zero, then it should be hex 0 and 0xE0.

[Paul Dixon]

Chris,
if the QUAD has a value of zero, then you are right but doesnt this QUAD have a value of 5.62958543355904E+16 which is 00C800C800000000 in hex? The last 32 bits are zero.

Paul.

[Chris Holbrook]

Paul, I thought it was zero, but your explanation is plausible, will have to recreate it to test.

[Chris Holbrook]

Paul, you are right.