The length of tptr$ is just over 37k, and it consists of
1 2 12 7 221 21 5 (etc.)
Val(tptr$) gives a zero. In the bit of code below, the values
are obtained by extracting each space=terminated number into
o$, where it does have a value.
Not a problem, but may be of interest.
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1 2 12 7 221 21 5 (etc.)
Val(tptr$) gives a zero. In the bit of code below, the values
are obtained by extracting each space=terminated number into
o$, where it does have a value.
Code:
Tptr$=Trim$(Tptr$)+" " o$=Left$(tptr$,InStr(tptr$," ")) While Val(o$)>0 tpt&=Val(o$) m$=refLst$(tpt&) Control Set Text ArcDlg&, 1001, Str$(tpt&)+" "+Left$(m$,36) Put$ frf&, m$ Tptr$=Right$(Tptr$,Len(Tptr$)-InStr(Tptr$, " ")) Tptr$=Trim$(Tptr$)+" " o$=Left$(tptr$,InStr(tptr$," ")) Wend
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