Help: Passing array member of UDT

[Mike Joseph]

Hi folks,
Hopefully someone can provide me with a quick answer to this one
because its been stumping me for the last 10 minutes.

Why cant I pass the byte array element of my udt, the same
way that I can pass a regular byte array that is not a member
of a udt? How would I correctly pass that udt member?

Thanks in advance!
-Mike

#COMPILE EXE
#DIM ALL

TYPE UDT
    B(0 TO 5) AS BYTE   
END TYPE

FUNCTION PassByteArray( B1() AS BYTE) AS LONG
    MSGBOX "Success"
END FUNCTION

FUNCTION PBMAIN()
    DIM b() AS BYTE
    DIM lRet AS LONG
    DIM u AS UDT
    
    Redim b(0 to 5)
    
    'lRet = PassByteArray( u.b())   <-- This fails
    lRet = PassByteArray(b())       <-- This works
    
END FUNCTION

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[Semen Matusovski]

Mike --
array in UDT is not an array at all.
Compiler simply calculates offsets and doesn't create a descripter.
That's why pass address of first element + no. of elements.

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E-MAIL: [email protected]

[Mike Joseph]

Thanks for the fast response. Gonna have to re-think my
design here... i dont really want to have to pass two
parameters for this if i can avoid it. Maybe instead of
bytes i'll just use asciiz.
-Mike


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