Endians are attacking - Help

[Semen Matusovski]

PB/DLL uses native format for x86 PCes - Little Endian.
If x is long and x = &H01020304, at address VarPtr(x) is located &H04; VarPtr(x) + 1 - &H03...
But, of course, Hex$(x, 8) will display 01020304.

  #Compile Exe
  #Register None
  Type strTest
    One As Long
    Two As Long
  End Type

  Function PbMain
     Dim x As strTest
     x.One = &H01020304
     x.Two = &H55667788
     MsgBox Hex$(x.One, 8)
     MsgBox Hex$(x.Two, 8)
     Dim b As Byte Ptr
     b = VarPtr(x)
     MsgBox Hex$(@b[0], 2) + Hex$(@b[1], 2) + Hex$(@b[2], 2) + Hex$(@b[3], 2)
     MsgBox Hex$(@b[4], 2) + Hex$(@b[5], 2) + Hex$(@b[6], 2) + Hex$(@b[7], 2)
  End Function

[This message has been edited by Semen Matusovski (edited February 15, 2001).]

[Ben Clark]

I am wondering what the native format is in PBDLL.
If I create a long variable and place a value it,
then use the BIN$(LongVariable, 32),
I see the value in Big Endian format.
If I have a structure with several long fields,
and I just grab all the bytes from the structure,
will the bytes be in Big Endian or Little Endian.

Type strTest
One as Long
Two as Long
End Type

Union uTest
All as String * 8
Indi as strTest
End Union

GLOBAL Struct as uTest

Will Struct.All be the 2 longs in Big Endian order?
Does PBDLL have an easy way of converting between the different
Endian type?

Thanks



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