Converting RGB long back to three seperate numbers

[RyanCross]

This is probaly an easy question. YOu know when oyu use the RGB function to convert 3 numbers into an RGB long? Well I want to do the opisite. I want to convert an RGB long back to the 3, 0 - 255 values.

rgb& = RGB(126, 25, 38)

rgb& is now equal to: 2496894

How do I convert rgb& back to 126, 25 and 38?

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Thank you,
Ryan M. Cross
Webmaster FlexiFish Inc. UK
Likuid Creations Inc.

[Timm Motl]

Ryan:

   Temp&  = RGB(126, 25, 38)  ' 2496894


   Red&   = Temp& MOD 256
   Green& = (Temp& \ 256) MOD 256
   Blue&  = ((Temp& \ 256) \ 256) MOD 256

Timm

[Semen Matusovski]

I prefer Redim At

   #Compile Exe
   Function PbMain
      Dim cRgb As Long
      ReDim cbRgb(3) As Byte At VarPtr(cRgb)
      cRgb = Rgb(126, 25, 38)
      MsgBox "R =" + Str$(cbRgb(0)) + " G =" + Str$(cbRgb(1)) + " B =" + Str$(cbRgb(2))
   End Function

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[mark smit]

Here ya go...

#compile exe
#register none
 
sub ExtractRGB(byval rgbColor as long,Red as byte,Green as byte,Blue as byte)
    !mov eax,rgbColor
    !mov ebx,Red
    !mov [ebx],al
    !shr eax,8
    !mov ebx,Green
    !mov [ebx],al
    !shr eax,8
    !mov ebx,Blue
    !mov [ebx],al
end sub
 
 
 
function pbmain as long
    dim rgbColor as long
    dim Red as byte
    dim Green as byte
    dim Blue as byte
    
    'Red = 10
    'Green = 20
    'Blue = 30
    
    rgbColor = rgb(10,20,30)
    
    ExtractRGB rgbColor,Red,Green,Blue
    
    msgbox format$(Red,"Red = # ") & $CRLF & format$(Green,"Green = # ") & $CRLF & format$(Blue,"Blue = #")
end function

Hope this helps!


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Cheers!