Replace $CRLF

[Scott Turchin]

Why does this fail:
Local sTmp As String
Replace $CRLF With "|" In sTmp

But yet Tally(sTmp,$CRLF) returns 2


The string has two $CRLF's in it...

Is this a known issue?


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Scott

[Eric Pearson]

Works fine for me. Maybe you need the ANY option in the REPLACE?

If that's not it, please post a compilable program that fails.

-- Eric

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[Scott Turchin]

I thot it had worked in the past for me too...weird...

g_sCLipText is equal to this:
Wednesday, June 27, 2001, At 2:30 PM, by turchinsp on COMPUTERNAME
Wednesday, June 27, 2001, At 2:31 PM, by turchinsp on COMPUTERNAME

sTmp = g_sClipText
Replace $CRLF With "|" In sTmp
lCount = Tally(sTmp,"|") 'Used as $CRLF since it is encryptable..


hMMM I'll play wiht it a bit more, I'm having another issue that may be related, may be the cause of my issue...


Thanks

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Scott

[Scott Turchin]

Problem solved, I was doing it correclty, but when I wrote the encrypted/decrypted data to disk I was writing the g_sCliptext not the sTmp...


DOH!




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Scott