C to Pb (again...)

[Peter Lameijn]

I need to translate some c code. The C code is:

Int      mask
Int      seg
Int      pcm_val
unsigned char aval
 
#define	QUANT_MASK	(0xf)
 
aval|= (pcm_val >> (seg + 3)) & QUANT_MASK

Is this the right translation:

shift right pcm_val, seg+3
aval = (aval Or pcm_val) And %QUANT_MASK

In the C code, is pcm_val itself shifted, or is only the result used and pcm_val itself unchanged?
Is the default shift in C signed or unsigned?


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Regards,
Peter

[This message has been edited by Peter Lameijn (edited October 04, 2005).]

[Paul Dixon]

Peter,
is it not easier to write this code in PB from scratch?
Actually, I think it may be even easier to write it in ASM.

Check out one of the many references online. This one seems clear: http://www.epo.pucrs.br/~decastro/pdf/spra163a.pdf

See pages 16 and 17 for the easy to understand tables and you'll see what your code needs to do.
If nothing else, it might help you understand what the C code is doing so you can translate it more easily!

Paul.


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[Donald Darden]

That looks like a not equal rather than an equal operator in the
original.

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Old Navy Chief, Systems Engineer, Systems Analyst, now semi-retired

[Peter Lameijn]

That looks like a not equal rather than an equal operator in the original.

No, x |= y is a compound assignment operator, translates as x = x or y
(You probably mixed it up with x != y, which is not equal...)

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Regards,
Peter